ふうよしまた少し賢くなったぞ Ok, I'm a little smarter now

1 問題1 Problem1

海外の皆様日本語の文章の後に英語訳があります

問題2 Problem

For those of you overseas, there is an English translation after the Japanese text.

ふうよしまた少し賢くなったぞ　Ok, I'm a little smarter now

見た目が同じ9枚の金貨がある。その中の1枚は他よりわずかに軽い偽金貨である。

天秤を使って偽金貨を特定したい。

ここには天秤が4つある。しかし、この中の1つの天秤は不良品である。

不良品は“右に傾く”、“左に傾く”、“釣り合う”の中からランダムな結果を出してしまう。

4つの天秤のうちどれが不良品かは分からない。

天秤をそれぞれ1回使って偽金貨を確実に見つけるにはどうすればよいか？

最初はこの質問の回答者の解けたという回答がわかりにくく理解できず疑ってしまったけど

ネットで見た金貨九枚から一枚偽ものを天秤を二回使い答えを出すというところから考えて答えを出してこの質問の回答者の解けたという回答をその時正しいと理解した

それを理解するためにお勧めされたユーチューブのパラドクス問題天秤の動画は見なかったけど

教本資料頼る人なく全て頭で考え十分くらいで答えが出た

ランダム性を確かめる方法がないと思い込んでよく考えなかった先入観はいかんと学んだな

そして答え当然わかりやすく

一つ不良品の天秤があっても四つの天秤に両方で調べていないの一枚づつのせて金貨を入れ替えて片方三枚両方で六枚で全部入れ替えて金貨全部確実来を得るため金貨一枚を除外し一枚数回づつか確かめていって上がるか下がる金貨の六枚から正常な天秤で測った金貨を覗き答えを出す問題

ランダムが釣り合うじゃないなら釣り合う天秤は必ず二つある

残り二つが怪しいのでその残りの二つの天秤で測ったの六枚は除外し残り二つを使い本物のか確かめた金貨から逆算する

釣り合う天秤が三つなら最後の四つ目の判定から逆算する

これは私が書いたのものではないけど

金貨九枚に番号をつけて

① 123 456 (789はのせない

② 147 258 (369はのせない

③ 168 357 (249はのせない

④ 267 348 (159はのせない

こんな感じこれは最後の天秤に乗せる9の一枚が偽ものの金貨としたときの答え

違った場合もこれで判断できる

一枚除外して確かめられる金貨の数を増やし一枚三回確かることで不良品にであったときでも確実に9枚から一枚偽物の金貨が見つかるわけだ

興味あるなら各自正しいかやってみてね

さてどれくらいむずかしい問題なのかようわからん

解く前はまとも回答ないと思い込んでいたけど

そして全く生きていない学校の算数まともに覚えていないので貢献度まるでなし

当然パラドクス問題の内容など見たこと聞いたことも習ったこともない

今日パラドクス問題の概要を知った始末

そしてこれが作家の何の役に立つのかそれは先入観からの思考停止という愚行が学べた

ついでに海外の目に留まれば作家になったとき話題になりそうなので作品として投稿

日本語版のここまでの分かりやすさはよく理解してるからだよ

よく理解していないと誰にでもわかりやすくは難しい

これは教科書資料からだと中々難しい技の一つ

まあそうすることで聞く者の自分で考え学ぶ自己学習力を下げるということあるから誰にで分かりやすい説明がすべていいとは違うけどね

ふうよしまた少し賢くなったぞ　Ok, I'm a little smarter now

There are nine gold coins that look identical. One of them is a fake coin that is slightly lighter than the others.

You want to identify the fake coin using a scale.

There are four scales here. However, one of them is defective.

The defective scale will give a random result from among "tipping to the right", "tipping to the left", or "balanced".

You don't know which of the four scales is defective.

How can you use each scale once to reliably find the fake coin?

At first, I was skeptical of the answer given by the person who answered this question because I found it difficult to understand.

I found the answer by using one fake gold coin out of nine coins I saw online, then used the scales twice to get the answer, and I understood then that the answer given by the person who answered this question was correct.

I didn't watch the recommended YouTube video on the balance paradox problem to understand it, but I was able to get the answer in about ten minutes without relying on textbook materials or anyone else.

I learned that it's no good to have preconceived notions that don't give much thought because you think there's no way to check for randomness.

And the answer was of course easy to understand.

Even if there is one defective scale, Place one coin that has not been checked on each of the four scales, swap them, and swap all three on each side to get a sure result for all the coins. Remove one coin and check each one several times to see if it goes up or down. Look at the coins measured on the normal scale from the six coins to get the answer.

If it's not a random balance, there must be two scales that balance.

The remaining two are suspicious, so remove the six coins measured on the remaining two scales and use the remaining two to count backwards from the coins that were checked to see if they were real.

If there are three scales that balance, count backwards from the last judgment of the fourth one.

This isn't something I wrote, but

Number the nine gold coins.

① 123 456 (789 cannot be placed

② 147 258 (369 cannot be placed

③ 168 357 (249 cannot be placed

④ 267 348 (159 is not included.

This is the answer when one of the last 9 coins placed on the scale is a fake coin.

Even if it is wrong, you can still determine this.

By removing one coin and increasing the number of coins that can be checked, you can check one coin three times, so even if you encounter a defective coin, you can be sure to find one fake coin out of the 9 coins.

If you're interested, try it out and see if it's correct.

I don't know how difficult this problem is.

Before I solved it, I thought there was no good answer.

And I don't remember my school math properly, so I'm not contributing much.

Of course, I've never seen or heard anything about the contents of the paradox problem. I have never been to or learned about the paradox problem

Today I learned the outline of the paradox problem

And what use is this for a writer? I learned about the foolishness of stopping thinking due to preconceptions

In addition, if it catches the attention of people overseas, it will become a topic of conversation when I become a writer, so I am posting it as a work

The reason why the Japanese version is so easy to understand is because I understand it well

If you don't understand it well, it's difficult to make it easy for everyone to understand

This is one of the difficult techniques to use from textbook materials

Well, doing so can lower the listener's ability to think and learn for themselves, so not all explanations that are easy for everyone to understand are good